签到
错误输入一次后在url框中发现false,修改为true后获得flag
喜欢做签到的 CTFer 你们好呀
题目要求ctf战队招新网站,在承办单位中找到,进去后为Linux终端
flag1
通过help命令找出可用命令,再用ls -la命令找到隐藏的.flag文件,cat .flag获得
flag{0k_175_a_h1dd3n_s3c3rt_f14g___please_join_us_ustc_nebula_anD_two_maJor_requirements_aRe_shown_somewhere_else}
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flag2
输出.oh-you-found-it的内容,提示考虑其他目录,进入Awards时提示要管理员权限,但是sudo su时跳转奶龙
尝试其他命令在输入env(显示环境变量)时发现flag在环境变量中
flag{actually_theres_another_flag_here_trY_to_f1nD_1t_y0urself___join_us_ustc_nebula}
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比大小王(未完成)
源码有些看不懂,看题解在控制台直接粘贴该代码获得flag
function f() { // 只要还没到 100 分 if (state.score1 < 100) { // 选择正确的答案 if (state.value1 < state.value2) { chooseAnswer('<'); } else { chooseAnswer('>'); } // 1 毫秒后再次调用 f 函数 setTimeout(f, 1); } } f(); function chooseAnswer(choice) { if (!state.allowInput) { return; } state.inputs.push(choice); let correct; if (state.value1 < state.value2 && choice === '<' || state.value1 > state.value2 && choice === '>') { correct = true; state.score1++; document.getElementById('answer').style.backgroundColor = '#5e5'; } else { correct = false; document.getElementById('answer').style.backgroundColor = '#e55'; } document.getElementById('answer').textContent = choice; document.getElementById('score1').textContent = state.score1; document.getElementById('progress1').style.width = `${state.score1}%`; state.allowInput = false; setTimeout(() => { if (state.score1 === 100) { submit(state.inputs); } else if (correct) { state.value1 = state.values[state.score1][0]; state.value2 = state.values[state.score1][1]; state.allowInput = true; document.getElementById('value1').textContent = state.value1; document.getElementById('value2').textContent = state.value2; document.getElementById('answer').textContent = '?'; document.getElementById('answer').style.backgroundColor = '#fff'; } else { state.allowInput = false; state.stopUpdate = true; document.getElementById('dialog').textContent = '你选错了,挑战失败!'; document.getElementById('dialog').style.display = 'flex'; } }, 1); // 这里的 200 改成了 1 }
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flag{I-am-tHE-hAckEr-king-0F-C0mPar!Ng-NUM6ErS-z024}
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Node.js is Web Scale(未完成)
PaoluGPT(未完成)